0.2 Grams of HCL is dissolved in 0.8g of water. The density of the solution formed is 1.10g/ml.

What is the molarity of the solution????

%HCl = [0.2/0.2+0.8)]x100 = 20%
Density = 1.10 g/mL.
The mass of 1,000 mL is 1.10 g/mL x 1,000 mL = 1100 grams.
Mass HCl in the 1100 g is 1100 x 0.2 = 220 grams (the 0.2 is the 20%).
Convert 220 grams to mols.
That is mols/1,000 mL or mols/L and that is molarity.

To calculate the molarity of the solution, we need to determine the number of moles of HCl present in the solution. We can use the given percentage of HCl and the density of the solution in order to calculate this.

First, we calculate the mass of HCl in the solution. The mass percentage of HCl is given as 20%, so we can calculate the mass of HCl in grams using the following equation:

Mass of HCl = %HCl x Total mass of solution
Mass of HCl = 20% x (0.2 g + 0.8 g) = 0.2 g

Next, we have the density of the solution, which is given as 1.10 g/mL. From this, we can calculate the total mass of the solution by multiplying the density by the volume:

Total mass of solution = Density x Volume
Total mass of solution = 1.10 g/mL x 1,000 mL = 1,100 g

Now, we have the mass of HCl (0.2 g) and the total mass of the solution (1,100 g). We can convert the mass of HCl to moles using the molar mass of HCl, which is 36.5 g/mol:

Moles of HCl = Mass of HCl / Molar mass of HCl
Moles of HCl = 0.2 g / 36.5 g/mol ≈ 0.0055 mol

Lastly, we can calculate the molarity of the solution by dividing the moles of HCl by the volume of the solution in liters:

Molarity = Moles of solute / Volume of solution in liters
Molarity = 0.0055 mol / 1 L = 0.0055 M

Therefore, the molarity of the solution is approximately 0.0055 M.