Can somebody pls help me with this?
For the equation below find the net balanced equation:
Ag + NO3- --> Ag+ + NO
(Note: This reaction takes place in an acidic solution.)
This is what I got:
3Ag + NO3- + 4H+ --> 3Ag+ + NO + 2H2O
right
Yes, you are correct!
To balance this equation, we need to make sure that the number of atoms of each element is the same on both sides of the equation. Here's how you can do it:
1. Start by balancing the elements that appear in only one reactant and one product. In this case, we have silver (Ag) and nitrogen (N).
2. Balance the Ag atoms first. On the left side, we have 1 Ag atom, and on the right side, we have 3 Ag atoms. To balance the Ag atoms, put a coefficient of 3 in front of Ag on the left side.
3Ag + NO3- + 4H+ --> 3Ag+ + NO
3. Next, balance the N atoms. On the left side, we have 1 N atom, and on the right side, we have 1 N atom. Since N is already balanced, we can move on to the next step.
3Ag + NO3- + 4H+ --> 3Ag+ + NO
4. Now, balance the O atoms. On the left side, we have 3 O atoms from NO3- and 4 O atoms from H2O (which comes from the H+ and OH- ions in the acidic solution). On the right side, we have 1 O atom from NO. To balance the O atoms, put a coefficient of 2 in front of H2O on the left side.
3Ag + NO3- + 4H+ --> 3Ag+ + NO + 2H2O
5. Finally, balance the H atoms by putting a coefficient of 3 in front of H+ on the right side.
3Ag + NO3- + 4H+ --> 3Ag+ + NO + 2H2O
And there you have it! The net balanced equation is 3Ag + NO3- + 4H+ --> 3Ag+ + NO + 2H2O.