Which elements result if two protons and two neutrons are ejected from a radium nucleus with atomic number 88 and mass number 226?
What element is atomic number 86 and mass 222?
Sorry, should be atomic number 88.
Huh? It ejected two protons, changing the number of protons in the nucleus to 88-2=86
To determine which elements result from the ejection of protons and neutrons from a radium nucleus, we need to consider the atomic number and mass number of radium.
Radium has an atomic number of 88, which represents the number of protons in its nucleus. The mass number is 226, which represents the sum of protons and neutrons in the nucleus.
In the given scenario, two protons and two neutrons are ejected from the radium nucleus. This means that the atomic number of the resulting element will decrease by 2, while the mass number will decrease by 4.
Initially, the atomic number of radium is 88. If we subtract 2 protons, we get 88 - 2 = 86. Thus, the atomic number of the resulting element is 86.
The mass number of radium is 226. If we subtract 2 protons and 2 neutrons, we get 226 - 2 - 2 = 222. Therefore, the mass number of the resulting element is 222.
Based on this information, the element with atomic number 86 and mass 222 is radon (Rn).