Math
posted by DrBob222 .
3x4 to y+15
is constant and
y=3 when x=2
then when
y=12, x equals?
My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.
My Steps:
3xy:y+15 The original problem above says 3x4 and not 3xy. Try it again. I have 7/3 for the answer.
3x12:12+15
3x12:27
1227:3x
39:3x
13:x
I'll try again:
3x4:y+15
3x:12+15+4
3x:31
Now what. Is what I did right?
I need help with this problem.
Given that the ratio of
3x4 to y+15
is constant and
y=3 when x=2
then when
y=12, x equals?
My answer was 13. Im not sure how to solve this question. Could you please go through the steps so I can see they match up with mines.
My Steps:
3xy:y+15
3x12:12+15
3x12:27
1227:3x
39:3x
13:x
The problem said the ratio was a constant when x=2 and y=3
I substituted x = 2 and y=3 and solved for the constant.
(3x4)/(y+15) = k
I found 1/9 for k.
Then I started anew, substituted y=12 and solved for x.
There may be an easier way to do it but I think this will work.
I tried that did I not. I honestly don't understand. Can you please type it out.
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