the problem states.
find the slope of any line perpendicular to the line through points (3,3) and (2,8).
so did the formula
m= (y2-y1)/(x2-x1)
and from it i got -5
so the slope is -5
and anyline perpendicular to this sloe would be positive 5 is that correct.
no. the slope perpendicular to slope b is -1/b.
so it would be +1/5.
To find the slope of any line perpendicular to another line, you need to find the negative reciprocal of the slope of the given line.
In this case, the given line passes through the points (3,3) and (2,8). By using the formula for slope, m = (y2-y1)/(x2-x1), you correctly found the slope of the given line to be -5.
To find the slope of a line perpendicular to this, you need to find the negative reciprocal. The negative reciprocal of -5 is 1/5.
So, any line perpendicular to the line passing through the points (3,3) and (2,8) will have a slope of 1/5.