6a^2+4a+5+3a^2+7a-2

That is the same thing as 9a^2+11a+3, but what is the question? You have just written an algebraic expression, not an equation to be solved.

assuming you are required to factorise the equation and the expression give by drwls it factorises to

(9a+3)(a+1)

hope this helps

To factorize the expression 6a^2+4a+5+3a^2+7a-2, you can follow these steps:

Step 1: Combine like terms.
Combine the terms that have the same variable and exponent:
(6a^2 + 3a^2) + (4a + 7a) + (5 - 2)
This simplifies to:
9a^2 + 11a + 3

Step 2: Factorize the expression.
To factorize the quadratic expression 9a^2 + 11a + 3, you can look for two binomials that multiply together to give this expression. The factors will have the form (ma + b)(na + c), where m, n, b, and c are constants that you need to determine.

To find the factors, you need to find two numbers that multiply to give 9 (the coefficient of a^2) and add up to give 11 (the coefficient of 'a'):

The numbers that fit these criteria are 9 and 1:
9 * 1 = 9
9 + 1 = 10

Therefore, the expression can be factored as:
(9a + 3)(a + 1)

Note: Factoring is a useful technique in algebra to simplify expressions and solve equations.