math,algebra,help
posted by Jasmine20 .
Okay now i need explanation how to do these types of problems.
Directions: Divide
Problem:
(7x^5y^521x^4y^4+14x^3y^3)/(7x^3y^3)
Realize that you have 7x^3y^3 on the bottom. Now in order to get rid of that, you want to have the same thing in the top, multiplied by something else. That way, the 7x^3y^3 on the top and bottom will cross out, because any number over itself is 1. So, take out 7x^3y^3 from the numerator:
[7x^3y^3(x^2y^23xy+2)]/(7x^3y^3)
Now once you cross out the (7x^3y^3) from the fraction, you are left with x^2y^23xy+2. So, to factor this, you need the beginnings of the parentheses to be xy, so when you multiply xy times xy you will get x^2y^2.
(xy )(xy )
Now, you know that the ends of the parentheses must multiply to 2, so they will be 2 and 1, but we don't know if they are positive and negative yet.
(xy 2)(xy 1)
Now, you want the outer terms multiplied plus the inner terms multiplied to equal negative 3. So, if the 2 and 1 were positive, we'd end up with +3 and we want 3, so we know the signs inside must be negative:
(xy2)(xy1)
where did you get:
[7x^3y^3(x^2y^23xy+2)]/(7x^3y^3
the 3xy+2
I took out 7x^3y^3 from everything in the numerator. So, from the 7x^5y^5, I took out 7x^3y^3 and separated it from x^2y^2, because if you multiply those 2, you will end up with the original 7x^5y^5. I did the same for 21x^4y^4. If you remove from that 7x^3y^3 (basically, what will you multiply by 7x^3y^3 to get back to 21x^4y^4?), you will get 3xy. For the last part, 7x^3y^3 times 2 is the original, 14x^3y^3. Wow, that sounds way more confusing than it is. If you ask your teacher to show you it is much easier written and pointed out than me trying to explain it on here.

3y divided by 7
Respond to this Question
Similar Questions

to bobpursley,math
This is what i have am i wrong or correct.Or how can word it or modify it to be with what the directions are asking? 
Question, in regards to math
My questions is this: Directions :create one statement in english representing an algebraic representation. I have this: SIMPLE PROBLEM: A DOZEN EQQS COST $1.20. WHAT IS THE PRICE OF EACH (1) EGG. ALGEBRAIC REPRESENTATION OF THIS PROBLEM, … 
math,correction
can someone correct these for me i'll appreciate it thank. dirctions: solve 3x7=2x+8 my answer: x = 15 directions: solve 2/5x=10 my answer: x = 25 Directions: solve 3(x+1)=2(x8)+3 my answer: x= 3.2 1 looks ok. Show your work … 
Math
I have 2 problems I need help with both I have narrowed it down to 2 possible answers but can't decide which one is right. The first problem log subscript 5 (2x+3)=2 the choices a)13/2 and b) 14. The next problem 8^x = 16^x+2 the choices … 
math
how to work out 9x+1710x=21x+23 its 43 duhhhhhhhhhhhhhhhhhhhh that isn't worked outttttttttttttttttttttttttt!~ It's not worked out  nor is her answer correct. So if someone says, "duhhhhhh," don't feel too badly. She obviously … 
Algerbra
how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will do the left side.. 21x + 29= Now, subtract sixteen x from both sides, and subtract 28 from both sides. I will be happy to check your work. 7(3x+4)=8(2x+5)+13 21x + … 
algebra
A coffee merchant has coffee beans that sell for $9 per pound and $12 per pound. The two types are to be mixed to create 100 lb of a mixture that will sell for $11.25 per pound. How much of each type of bean should be used in the mixture? 
algebra
I need help with this problem: Dividing 7x^5y^521x^4y^4+14x^3y^3/7x^3y^3 
Chemistry
can anyone help me on my chemistry problem. i need a merck index to solve this. i have a PH of 10.7 and the nearest solution that is near to it is 10.32. The solution that is 10.32 is NaHCO3. i subtract both of them to get the ratio … 
algebra
find the product of (x^23x+5)with the quotient of (21x^6 14x^57x^3)divide by 7x^3