thanks,can you help me with this one:
xy-3x-8y+24
I know you have to go, but you should be able to figure these out by now. Take out x from the first 2 and 8 from the second 2:
x(y-3)-8(y-3)
(x-8)(y-3)
ac-bc+ad-bd
*I seriously only have 2 more minutes now,I told my mom I needed to write something really quick!!Please help me,you have to factor by group
Take out c from the first 2 and d from the second 2:
c(a-b)+d(a-b)
(c+d)(a-b)
To factor the expression xy - 3x - 8y + 24, you can use grouping. Here's how you can do it step by step:
Step 1: Group the terms in pairs.
(xy - 3x) - (8y - 24)
Step 2: Take out the common factor from each group.
x(y - 3) - 8(y - 3)
Step 3: Notice that both groups have a common factor of (y - 3). Factor it out.
(y - 3)(x - 8)
So, the factored form of xy - 3x - 8y + 24 is (y - 3)(x - 8).
If you have an expression like ac - bc + ad - bd, you can also use grouping to factor it. Here's how:
Step 1: Group the terms in pairs.
(ac - bc) + (ad - bd)
Step 2: Take out the common factor from each group.
c(a - b) + d(a - b)
Step 3: Notice that both groups have a common factor of (a - b). Factor it out.
(a - b)(c + d)
So, the factored form of ac - bc + ad - bd is (a - b)(c + d).
Remember, factoring by grouping involves grouping terms with common factors together and then factoring out the common factor from each group.