physics (cross product vectors)
posted by steve .
Two vectors are lying in the xz plane: A=2.00i + 3.00k and B= -9.00i + 2.00k.
a) What is the value of AxB?
Check my solution: I found through calculations that the value is 23j.
b) What is the magnitude |AxB|?
I could do ABsin theta, but I have no angle between. So am confused here.
C) What is the ganle between the two vectors.
Here I could do the:
---- = sin theta.
Please help. I really would like to know this concept before class today in about 1 hr. Check all my answers, please.
(2.00i + 3.00k)(-9.00i + 2.00k)
from that, 4(-j) + 27(-j)
magnitude: (sqrt (4^2 + 27^2))
angle between vectors?
I'm still somewhat confused. Does 4(-j) + 27(-j) equal -31j?
also, if you can, please elaborate a bit more on proper steps to conceptualize prob(the rest).
yes, I got -31j
if the cross product is equal to magnitude A * magnitude B * sinTheta, then
Solve for Theta.