physics... part a on

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A diver descends from a salvage ship to the ocean floor at a depth of 35 m below the surface. The density of ocean water is 1.025x10^3 kg/m^3.

a) Calculate the guage pressure on the diver on the ocean floor.

b) Calculate the absolute pressure on the diver on the ocean floor.

The diver finda a rectangular aluminum plate having dimensions
1.0m x 2.0m x 0.03m. A hoisting cable is lowered from the ship and the diver connects it to the plate. The density of aluminum is 2.7x10^3 kg/m^3. Ignore the effects of viscosity.

c) Calculate the tension in the cable if it lifts the plate upward at a slow, constant velocity.

d) Will the tension in the hoisting cable increase, decrease, or remain the same if the plate accelerates upward at 0.05m/s^2? Justify your answer.



ok for a im going to let e = roh...

so P = Po + egh
P=(1.025x10^3)(10)(35)

so my answer to a wiill be 358750??

yes, see below. The units are in pascals.

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