determine the x-intercepts for the function
y=2x^2+5x-3
Factor this:
0=2x^2+5x-3
That gives the roots.
i agree with bobpursley's statement as long as the numbers 2 5 and 3 are not squared or 2! 5! 3! then it would change the problem
To determine the x-intercepts of the function y = 2x^2 + 5x - 3, we need to find the values of x for which y equals zero. In other words, we want to solve the equation 2x^2 + 5x - 3 = 0.
One way to find the x-intercepts is by factoring the quadratic equation. However, not all quadratic equations can be easily factored. In this case, let's use the quadratic formula to get the roots.
The quadratic formula states that for any equation of the form ax^2 + bx + c = 0, the solutions for x can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / 2a
For the equation 2x^2 + 5x - 3 = 0, we have a = 2, b = 5, and c = -3. Plug these values into the quadratic formula:
x = (-5 ± √(5^2 - 4 * 2 * -3)) / (2 * 2)
Simplifying further:
x = (-5 ± √(25 + 24)) / 4
x = (-5 ± √49) / 4
Since square root of 49 is 7, we have:
x = (-5 + 7) / 4 or x = (-5 - 7) / 4
Simplifying further:
x = 2 / 4 or x = -12 / 4
Simplifying the fractions:
x = 1/2 or x = -3
So the x-intercepts for the function y = 2x^2 + 5x - 3 are x = 1/2 and x = -3.