Can you help me solve this problem...?
A teacher said to a pupil:
To the nearest per cent, 1/6 is 17%
The pupil said:
So, to the nearest per cent, 2/6 must be 34%
Show that the pupil is wrong.
*How do you work it out?
it is 33% because:
the percentage repeats 3 which is lower than 5 so you don't round up, making the percent for 2/6 = 33%
Ah, sorry I was on stupid mode. Thanks for the help.
your welcome.
hey could you possibly help me with mine?
Sure, but I can't guarantee I'll be able to do it ;)
that's okay, i just need a hand with them, they are posted back a bit.
Ohh, God. Sorry Shay, I don't know how to do either of those questions.
I'm rubbish at maths :)
me too. but i have to do it. it sucks.
sus
No problem, I'll be happy to help you with your math questions. Just let me know what the questions are and I'll guide you step-by-step to solve them.
Of course, I'll be glad to help you solve the problem you mentioned.
To show that the pupil is wrong, we need to calculate the nearest percentage for 2/6 and see if it is 34% or not.
To calculate the nearest percentage, we need to divide the numerator by the denominator and multiply by 100. In this case, dividing 2 by 6 gives us 0.3333...
Now, to round this value to the nearest percent, we look at the decimal places. If the decimal place is less than 0.5, we round down, and if it is equal to or greater than 0.5, we round up.
In this case, the decimal place is 0.3 which is less than 0.5, so we round down. Hence, the nearest percentage for 2/6 is 33%, not 34%.
Therefore, the pupil's statement is incorrect. The nearest percentage for 2/6 is 33%, not 34%.
If you have any further questions or need assistance with other problems, please let me know!