Calc
posted by Brian .
y=ln(x+1) +ln(x1) find dy/dx
I have trouble with this problem since i'm not that familar with finding the derivative when they involve ln. Please show me how to solve this problem. I should have gotten 2x/(x^21)
The derivative of ln(x) is 1/x
So, you obtain
dy/dx = 1/(x+1) + 1/(x1)
Adding the fractions gives you the desired answer 2x/(x^21) .
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