Hi
Can anyone help me define the empirical formula for highest fluoride and hydride in ununhexium.
292 uuh
116
How is this reached...
Thanks
freddo
Uuh is in group 16 (or VIA depending upon the system being used) so its chemistry should be similar to O2, S8, Se, Po, etc.
S forms SF4 and SF6 so I would make an educated guess that the hexafluoride would be UuhF6. As to the hydride, H2O, H2S, and H2Se exist. So I would guess H2Uuh would be possible; ALTHOUGH these are not hydrides, as such, at least not the way I define a hydride. I define hydrides as hydrogen with an oxidation state of -1 while the above hydrogen compounds have an oxidation state of +1. In fact, I would guess that Uuh would not form a hydride as I have defined it.
Thank you Dr Bob...
Are you doing the OU course S103. If so, the answer you are looking for is on page 114, book 6. Good luck with the tma!
whoever said UUH has a valency of 6 re check it is 2
I'm really struggling with the same question, i think im just acting blonde but i am major confused can anyone help me please??? I've read all the above but it still makes no senses. Thanks
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The empirical formula for the highest fluoride in ununhexium (Uuh) can be determined based on the periodic table and the concept of valency.
Ununhexium is located in Group 16 of the periodic table, also known as the oxygen family or chalcogens. Elements in this group typically have a valency of 2, meaning they can form compounds by gaining or sharing two electrons.
To determine the empirical formula for the highest fluoride in Uuh, we can assume that Uuh will have a similar chemistry to other elements in Group 16. For example, oxygen forms compounds like O2, sulfur forms compounds like S8, and selenium forms compounds like Se. Based on these similarities, we can make an educated guess that Uuh would form a hexafluoride compound, UuhF6.
Now, moving on to the hydride. Hydrides are compounds that contain hydrogen with an oxidation state of -1. However, in the case of Uuh, it is unlikely to form a hydride in the traditional sense, as defined by an oxidation state of -1. While H2O, H2S, and H2Se are examples of compounds that contain hydrogen with an oxidation state of +1, we cannot assume that Uuh would form a similar compound with hydrogen.
In summary, based on the information available, the educated guess for the empirical formula of the highest fluoride in Uuh would be UuhF6. However, it is unclear if Uuh would form a hydride compound based on the traditional definition of hydrides.
It's important to note that the information provided is based on current knowledge and educated guesswork, as Uuh is a highly unstable and synthetic element that has not been extensively studied. Further research and experimentation may be needed to determine its exact chemical properties and compounds.
I hope this explanation clears up any confusion you had about the topic. If you have any more questions, feel free to ask!