precal
posted by eragon .
The smaller of 2 numbers is 10 less than 4 times the greater number. The bigger number is 19 more than the smaller one.
If x is the smaller number one equation is:
a)x+y=19
b)x=19y
c)y=x+19
d)x=y+19
I'm almost positive it is d I just want to check.
A second equation is:
a)x=4y10
b)x=4y+10
c)x=104y
d)x=(104)y
Again I'm pretty sure the answer is c, but want to make sure.
If x is the smaller number and y is the bigger number, and y is 19 more than x, how can x be y + 19? Think again.
x is 10 less than 4y. They tell you that. So how can (c) be consistent with that? It can't. Try again.
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