Find the slope of any line perpendicular to the line through points (0,5) and
(-3, -4).
the slope i get is = 3
so the slope of any line perpendicular would be the reciprocal of 3 which is
-3/1
is that the correct answer.
or do i have to word it differenly like y = -3/1x + 5 if i'm using points (0,5)
slope is not three. Recheck
isn't slope y2-y1/x2-x1
so then that would be:
-4-5/-3-0=-9/-3=3
Actually, the slope formula is correct. The slope of a line passing through two points (x1, y1) and (x2, y2) is given by (y2 - y1) / (x2 - x1).
Using the points (0, 5) and (-3, -4):
slope = (-4 - 5) / (-3 - 0)
= -9 / -3
= 3.
So, the slope of the line passing through these two points is indeed 3.
To find the slope of a line perpendicular to this line, you need to take the reciprocal of 3. The reciprocal of a number is 1 divided by that number.
Therefore, the slope of any line perpendicular to the line passing through the points (0, 5) and (-3, -4) is -1/3.
You can also express this perpendicular line in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. Using the point (0, 5) and the slope -1/3, the equation of the perpendicular line would be:
y = -1/3x + b.
To find the value of b, substitute the coordinates of the point (0, 5) into the equation:
5 = -1/3(0) + b
5 = b.
So, the equation of the perpendicular line would be y = -1/3x + 5.