posted by .

How do I write arcsin4 in the form a+ib. I know the answer but do not Know how to get to it

Take sinus of both sides:

4 = sin(a)cosh(b) + i cos(a)sinh(b)

Equate real and imaginary parts. You then see that you can put a = pi/2. And it then follows that b = arccosh(4)

Thanks for getting back so promptly , unfortunately i do not what you mean by take sinus of both sides. I have got the stage you have it is the very final stage I van not do

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. maths 2

    The original question I had was write arcsin4 in the form a+ib. I manage and understand how to get so far BUT How do I get from cosacoshb-isinasinhb=4 to 2m(pi)+/- iarccosh4 arcsin4 = a + b i ---> 4 = sin(a + bi) sin(a + bi) = sin(a)cos(bi) …
  2. Maths

    use the formula cos(x+iy)=cosxcosiy-sinxsiniy to find two imaginary numbers whose cosine is 3 cos(x+iy)=cosxcosiy-sinxsiniy = cos(x)cosh(y) - i sin(x)sinh(y) = 3 Equating imaginary parts gives: sin(x)sinh(y) = 0 You know that y cannot …
  3. calculus

    what is the anti-derivative on square root of cosh^2(x)?
  4. calc: arc length

    find the exact length of this curve: y = ( x^3/6 ) + ( 1/2x ) 1/2 <or= x <or= 1 im looking over my notes, but i'm getting stuck. here's my work so far: A ( 1 , 2/3 ) B ( 1/2 , 49/48 ) y' = [1/6 (3x^2)] + [1/2 (-1x^-2)] y' = ( …
  5. Mathematics - Trigonometric Identities

    Let y represent theta Prove: 1 + 1/tan^2y = 1/sin^2y My Answer: LS: = 1 + 1/tan^2y = (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y) = (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y) = (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y) = (sin^2y …
  6. TRIG!

    Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1 - (3/4)sin^2 2x work on one side only! Responses Trig please help! - Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 …
  7. Precalculus

    Can anyone help me with this question please!! Show that (cosh x)^2 - (sinh x)^2 = 1 for every real number x.
  8. Calculus 12th grade (double check my work please)

    1.)Find dy/dx when y= Ln (sinh 2x) my answer >> 2coth 2x. 2.)Find dy/dx when sinh 3y=cos 2x A.-2 sin 2x B.-2 sin 2x / sinh 3y C.-2/3tan (2x/3y) D.-2sin2x / 3 cosh 3yz...>> my answer. 2).Find the derivative of y=cos(x^2) …
  9. Calculus

    How to derive cosh (3x) in terms of cosh (x) and sinh (x) ?
  10. Mathematics

    If Z= [tan 2x -i(sin x+cos x)]/[1+i sin x] is completely imaginary, find x.(0<=x<=(pi/2) ) I understand that here we have to equate the real part to 0,but how do we isolate the real part.I tried multi plying both numerator and …

More Similar Questions