what is the equation of the line that passes through {negative 4, negative 1}and {0,7}?
A.Y=2X PLUS 9
B. Y=X/2 PLUS 7
C. 2X PLUS 7
D. Y= NEGATIVE 2X PLUS 7
Here's a way to approach your problem.
'm' represents slope.
'b' the y-intercept.
m = (y2 - y1)/(x2 - x1)
m = [7 - (- 1)]/[0 - (-4)]
m = 8/4 = 2
Now you can find 'b' using the first ordered pair (-4, -1).
[y - (-1)]/[x - (-4)] = 2
(y + 1)/(x + 4) = 2
y + 1 = 2(x + 4)
Can you take it from here to finish?
I hope this will help.
graPH EACH EQUATION- INDICATE ONTHE GRAPH THE X-INTERCEPT AND THE Y INTERCEPT
Y=-4
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To graph the equation y = -4, we need to plot the points that satisfy this equation.
First, let's find the x-intercept. The x-intercept is the point where the line crosses the x-axis, meaning the value of y is 0.
Substituting y = 0 into the equation y = -4, we get:
0 = -4
Since 0 is not equal to -4, there is no x-intercept for this equation.
Next, let's find the y-intercept. The y-intercept is the point where the line crosses the y-axis, meaning the value of x is 0.
Substituting x = 0 into the equation y = -4, we get:
y = -4
So, the y-intercept is (0, -4).
Now, we can plot the y-intercept on the graph, which is the point (0, -4).
The graph of the equation y = -4 is a horizontal line that passes through the point (0, -4).