Can someone please help me with this?

Solve x^3-3x^2-10x=0 by factoring.

Take out x.
x(x^2-3x-10)=0

For the polynomial inside the parentheses, you want factors of 10 that will add or subtract to give 3. 10 and 1 gives 11 or 9 so that is no good. But 5 and 2 are ok. 5*2=10 and 5-2=3.
x(x+2)(x-5)=0
I assume you can finish. If not repost and tell us exactly what you don't understand about it.

Would your answers be x=-2 and x=5?

Yes, but there is another answer too. Isn't x=0 (from first x) factored out?

Oh, yes! I was wondering if you do anything with that. Thank you.

You're welcome! And yes, you are correct. By factoring out x from the equation x(x^2-3x-10)=0, we do obtain the solutions x=0, x=-2, and x=5. It's important to consider all possible factors when factoring an equation.