math
posted by Jimmy
solve 2x^2+3x+8=0 and express the solutions in a+bi form.
Let's use the quadratic formula to solve for x and express those solutions in a+bi form.
x = [b + or  sqrt(b^2  4ac)]/2a
Note: sqrt = square root.
a = 2, b = 3, and c = 8 from your problem.
Therefore:
x = [3 + or  sqrt(3^2  4*2*8)]/2*2
x = [3 + or  sqrt(55)]4
x = [3 + or  i sqrt(55)]/4
Solutions:
x = [3 + i sqrt(55)]/4 = 3/4 + [sqrt(55)/4]i
x = [3  i sqrt(55)]/4 = 3/4  [sqrt(55)/4]i
I hope this will help.
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