math

posted by Jimmy

solve 2x^2+3x+8=0 and express the solutions in a+bi form.

Let's use the quadratic formula to solve for x and express those solutions in a+bi form.

x = [-b + or - sqrt(b^2 - 4ac)]/2a

Note: sqrt = square root.

a = 2, b = 3, and c = 8 from your problem.

Therefore:
x = [-3 + or - sqrt(3^2 - 4*2*8)]/2*2
x = [-3 + or - sqrt(-55)]4
x = [-3 + or - i sqrt(55)]/4

Solutions:
x = [-3 + i sqrt(55)]/4 = -3/4 + [sqrt(55)/4]i
x = [-3 - i sqrt(55)]/4 = -3/4 - [sqrt(55)/4]i

I hope this will help.

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