math

posted by .

Express y as a function of x. C is a positive number.


3 ln y= 1/2ln (2x+1) - 1/3ln (x+4) + ln C

ln y = (1/6)ln (2x+1) -(1/9)ln (x+4) + (1/3) ln C
y = e^ln y = e^[(1/6)ln (2x+1) -(1/9)ln (x+4) + (1/3) ln C]
= C^(1/3)* (2x+1)^(1/6) /(x+4)^(1/9)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math

    express as a function. c is a positive number ln y= 1n x + 1n C Make both sides of the equation an exponent of e. Remember that x^a * x^b = x^(a+b)
  2. math

    Express y as a function of x. The constant C is a positive number. ln y = ln x + ln C
  3. math

    Express y as a function of x. The constant C is a positive number. ln y = 9x + ln C
  4. Algebra

    Express as a single Logarithm and Simplify: 2/3ln(x^2+1)+1/2ln(x^2-1)-1/2ln(x+1)
  5. Algebra 2

    e^(x-2)-12^(2x+3)=0 Class is a college level math prep. Sorry for previous post being incomplete. I'm thinking: ln^(x-2)=ln12^(2x+3) (x-2)ln=(2x+3)ln12 xln-2ln=2xln(12)+3ln(12) xln-2xln(12)= 2ln+3ln(12) and not sure
  6. Math

    3ln(b) + 2ln(c) write as a single log. I have tried this problem so many ways. i don't know what to do with the 3 and the 2. do you multiply or use them as exponents or what
  7. Calculus

    Evaluate (integral) cot 2x dx. A. 1/2Ln sin 2x+C B. 1/2Ln cos 2x+C C. 1/2Ln sec 2x+C D. 1/2LN csc 2x+C
  8. Calculus

    In order to express the function y=12^19x+7 as a composition of two functions the outer of which is an exponential function,we would let u be equal to the inner function, u=19x+7, and then write y as a function of u, as follows: y= …
  9. PreCalculus - Need help, due tonight

    1. Rewrite the expression 1/2ln(x – 6) + 3ln(x +1) as a single logarithm. 2. Rewrite the expression 1/3[ln x – 2ln(1 – x)] as a single logarithm.
  10. Algebra

    Use the properties of logarithms to expand the expression. ln y(y+1)^5, I keep coming up with the same answer which is wrong. y^5ln(y)+5y^4ln(y)+10y^3ln(y)+10y^2ln(y)+ln(y)

More Similar Questions