The Law of Gravitation is represented by the formula Fg=G(m1m2/r2)
What would be the inverse of this function Fg-1? What would this force represent?
Can someone plz hurry and answer this for me
To find the inverse of the function Fg = G(m1m2/r^2), we need to solve for r.
The first step is to isolate r^2.
Divide both sides of the equation by Fg:
Fg / Fg = G(m1m2 / r^2) / Fg
1 = G(m1m2 / r^2Fg)
Next, multiply both sides of the equation by r^2Fg:
r^2Fg = G(m1m2)
Finally, isolate r^2 by dividing both sides of the equation by Fg:
r^2 = G(m1m2) / Fg
Now, to find the inverse function Fg-1, we swap the roles of Fg and r^2 in the equation:
Fg-1 = G(m1m2) / r^2
This inverse function, Fg-1, represents the force between two objects due to gravity when the distance between them is known. Given the values of G, m1, m2, and r, this function can be used to calculate the force.