A GAS OCCUPIES A VOLUME OF 584 ML AT A PRESSURE OF 12.01K PA AND A TEMPERATURE OF 303K. whEN THE PRESSURE IS CHANGES, THE VOLUME BECOMES 477ML. IF THERE HAS BEEN NO CHANGE IN TEMPERATURE, WHAT IS THE NEW PRESSURE? ........ PLEASE HELP ME WITH THIS ....THANKS SOOOOOOO MUCH .......
(12.01)*(584)=X*(477)
P1*V1=P2*V2
I agree with anonymous.
To find the new pressure, you can use the gas law equation P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given:
P1 = 12.01 kPa
V1 = 584 mL
V2 = 477 mL
T1 = T2 (no change in temperature)
Using the gas law equation P1V1 = P2V2, you can rearrange the equation to solve for P2:
P2 = (P1 * V1) / V2
Now, substitute the given values into the equation:
P2 = (12.01 kPa * 584 mL) / 477 mL
To simplify the calculation, make sure you use consistent units. Convert mL to L by dividing by 1000:
P2 = (12.01 kPa * 0.584 L) / 0.477 L
Now, divide the numerator and denominator to find the value of P2:
P2 = 14.71 kPa
Therefore, the new pressure is 14.71 kPa when the volume changes to 477 mL while the temperature remains constant.