The volume of a solid is given by V=pi x^2(lnx)^2. what is the approximate change in the volume when x is increased from 2.718 to 3.000?
dv= PI 2x(lnx)^2 dx + Pix^2 *2lnx * 1/x reduce that.
For x, use 2.718
dx= 3-2.718
check my thinking.
Yes, that is correct. After that, plug in the numbers and you get an answer of dV=9.630.
