Post a New Question

math

posted by .

-5y^3(y-6)+4y^3(y-7)

OK - first, distribute -5y^3 to the (y-6). You should get -5y^4+30y^3. Do the same thing by distributing 4y^3 to the (y-7), leaving you with 4y^4-28y^3. Then combine the y^4 terms and the y^3 terms to get the answer of -y^4+2y^3.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question