math
posted by oscar .
5y^3(y6)+4y^3(y7)
OK  first, distribute 5y^3 to the (y6). You should get 5y^4+30y^3. Do the same thing by distributing 4y^3 to the (y7), leaving you with 4y^428y^3. Then combine the y^4 terms and the y^3 terms to get the answer of y^4+2y^3.
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