how would i find an equation of a line that goes through points(1,6) and (3,10)??
thanks
A straight line is
y=mx+b
Substitute the points to make two equations.
6=m(1)+b
10=m(3)+b
Two equations; two unknowns, m and b.
Solve for m and b, then plug back into y = mx + b. That will the the equation for the straight line.
i don't understand?
You know how to solve two equations simultaneously. There are two unknowns, m and b. Solve them for m and b, list the values here and I will show you how to construct the equation for the line. Here are the two equations from above.
eqn 1: 6=m(1)+b
eqn 2: 10=m(3)+b
To start you in the right directin, here is what you do to solve the equations.
1. Multiply eqn 1 by -1
2. Add the result + eqn 2.
3. That will eliminate b. solve for m.
4. Plug m back into either equation and solve for b.
5. Post values for m and b and I shall show you how to write the equation for the line that passes through those points.
P=H-F/2H TO SOLVE FOR H
To solve for H in the equation P = (H - F) / (2H), you can use algebraic manipulation.
1. Multiply both sides of the equation by 2H to eliminate the denominator:
2H * P = H - F
2. Distribute the 2H to both terms on the right side of the equation:
2HP = H - F
3. Move all terms involving H to one side of the equation:
2HP - H = -F
4. Factor out H from the left side:
H(2P - 1) = -F
5. Divide both sides of the equation by (2P - 1) to solve for H:
H = -F / (2P - 1)
So, the equation to solve for H is:
H = -F / (2P - 1)