how do i change x^2-4x-32=0 into (x+4)(x-8)=0
x^2-4x-32=0
=> x^2-8x+4x-32=0
=> x(x-8)+4(x-8)=0
=> (x-8)(x+4)=0
OR (x+4)(x-8)=0
X2 -4x -32 = 0
JUst factor it. It factors into
(X-8)(X+4)=0
To change the equation x^2 - 4x - 32 = 0 into the form (x+4)(x-8) = 0, we need to factor the quadratic equation.
Step 1: Write down the quadratic equation: x^2 - 4x - 32 = 0.
Step 2: Look for two numbers that multiply to give the constant term (-32) and add up to give the coefficient of x (-4). In this case, the numbers are -8 and 4.
Step 3: Rewrite the middle term (-4x) using these two numbers: x^2 -8x + 4x - 32 = 0.
Step 4: Group the terms and factor by common factor: (x^2 - 8x) + (4x - 32) = 0.
Step 5: Factor out the common terms in each group: x(x - 8) + 4(x - 8) = 0.
Step 6: Notice that we have a common factor of (x - 8) in both terms. Factor out this common factor: (x - 8)(x + 4) = 0.
Now the equation x^2 - 4x - 32 = 0 is written in the factored form (x + 4)(x - 8) = 0.