Directions: Use what is given to write an equation of a line in STANDARD, SLOPE-INTERCEPT, AND POINT-SLOPE form.

1. m = 3 (0,4)
s=B4=3
si=3x+4
ps=y-4=3x

Are we doing these correctly?

I do not know what those forms mean, but if the line goes through (0,4) with slope 3, the equation is
y - 4 = 3 x
y = 3x + 4
which agrees with you "si"

I do not know what those forms mean, but if the line goes through (0,4) with slope 3, the equation is
y - 4 = 3 x
y = 3x + 4
which agrees with you "si"

Find the equation of the line that goes through the given point

and has the given slope and has the given slope. Write the answer in slope-intercept (-1, -5), -8

Yes, you have correctly written the equation of the line in slope-intercept form. The slope-intercept form of a linear equation is y = mx + b, where m represents the slope of the line and b represents the y-intercept.

In this case, the given slope is 3 and the line passes through the point (0, 4). To find the equation in slope-intercept form, you can substitute the values of the slope and the coordinates of the point into the equation.

To write the equation in standard form, which is Ax + By = C, we can rearrange the equation y = 3x + 4 as -3x + y = 4, or you can multiply both sides of the equation by -1 to get -y = -3x - 4.

To write the equation in point-slope form, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line, you can substitute the values of the slope and the coordinates of the point into the equation. In this case, it would be y - 4 = 3(x - 0), which simplifies to y - 4 = 3x.

So, the equation of the line in standard form is -y = -3x - 4, the equation in slope-intercept form is y = 3x + 4, and the equation in point-slope form is y - 4 = 3x.