What is the specific heat of Aluminom if it takes 1100 calories to take the temp. from 10 degrees C to 80 degrees C and the block of Aluminon has a mass of 60 grams?

q = massAl x specific heat x (Tf-Ti)
q is 1100 calories
Tf is final T
Ti is initial T
mass is 60g
solve for specific heat (in calories).

To find the specific heat of aluminum, we can rearrange the formula:

q = massAl x specific heat x (Tf-Ti)

Given data:
q (heat energy) = 1100 calories
Tf (final temperature) = 80 degrees C
Ti (initial temperature) = 10 degrees C
mass of aluminum (massAl) = 60 grams

Plugging in the values we know:

1100 calories = 60 grams x specific heat x (80 degrees C - 10 degrees C)

Simplifying the equation:

1100 calories = 60 grams x specific heat x 70 degrees C

To solve for the specific heat, we need to isolate it on one side of the equation. Dividing both sides of the equation by (60 grams x 70 degrees C):

specific heat = 1100 calories / (60 grams x 70 degrees C)

Calculating this value:

specific heat = 0.0262 calories/gram °C

Therefore, the specific heat of aluminum is approximately 0.0262 calories/gram °C.