A person pushes a 10 kg box from rest and accelerates it to a speed of 3.2 m/s with a constant force. If the box is pushed for a time of 2.6 s, what is the force exerted by the person?
force*time=mass*changeinvelocity
solve for force.
A person pushes a 10 kg box from rest and accelerates it to a speed of 3.2 m/s with a constant force. If the box is pushed for a time of 2.6 s, what is the force exerted by the person?
To calculate the force exerted by the person, we can use Newton's second law of motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration:
Force = mass * acceleration
We are given the mass of the box (10 kg) and the change in velocity (3.2 m/s). However, we need to find the acceleration first. To do this, we can use the following equation:
acceleration = change in velocity / time
In this case, the change in velocity is 3.2 m/s (the final velocity) minus 0 m/s (the initial velocity, since the box starts from rest), which gives us an acceleration of 3.2 m/s.
Now we can substitute the values into the formula for force:
Force = mass * acceleration
Force = 10 kg * 3.2 m/s
Force = 32 N
Therefore, the force exerted by the person is 32 Newtons.