math, algebra
posted by jasmine20
can someone correct this for me or help me.
6x^2y^3+ 9x^2y^3 divided by 3x^2y^2
my solving and answer is:
15 x x y y y
 = 5y
3 x x y y
Looks good to me. I've never thought of showing x^2y^3 as xxyyy. That a neat wrinkle. We see quickly that the Xs cancel and all but one y in the top cancel.
so the way i did it is correct
as well as the answer
yes.
how do i solve 186(5x8)=24
I think I take 6X5X and6X8=
1830x48=24
18 18
30x30=24
div 30
=x 30=24
24
so x= 6
or am I all misses up
THIS IS WHAT YOU DO
186(5X8)=24
1830X+48=24 iN THIS STEP YOU DO DISTRUBITION SUCH AS 6(5X)=30X, 6(8)=48
SO
1830X+48=24
6630X=24 thIS STEP YOU ADD THE 18+48=66, AND YOU JUST BRING DOWN THE 30X
now you have 6630x=24
so then you bring the 66 to the other side of the equation which you have to do the opposite so it should look like this
30x=2466
which will give you 30x=90
NOw to get the x alone you divided bothe sides by 30
x=90/30
x=3
TO check you just substitute
186(5x8)=24
186(5(3)8)=24
186(158)=24
186(7)=24
1842=24
24=24
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