I need to make 10 ml of bacitracin at 1 uM. I have purchased 5 mg of it. The MW of it is 458.6 g. How would I go about doing this and what would be my final answer? Thank you.
concentration= moles/volume= mass/(MW*volume)
or mass= concentration*volume*MW
= 1uM*10ml*458.6g/mole
= 4.586 g *10^-5 or 4.586mg
Put 4.586mg in a vial, add water to make 10 ml of solution, stir, label, and properly dispose of the excess chemical
To make 10 ml of bacitracin at a concentration of 1 uM, you can follow these steps:
1. Calculate the mass of bacitracin needed:
mass = concentration * volume * MW
In this case, the concentration is 1 uM (which is equivalent to 1 x 10^-6 moles per liter), the volume is 10 ml (which is equivalent to 10 x 10^-3 liters), and the MW (molecular weight) is 458.6 g/mole.
mass = (1 x 10^-6 moles/L) * (10 x 10^-3 L) * 458.6 g/mole
mass = 4.586 mg
2. Measure out 4.586 mg of bacitracin using a sensitive balance and transfer it to a vial or container.
3. Add water to the vial or container to make a total volume of 10 ml. Make sure the water is appropriate for your desired application (e.g., sterile water for injection if it is for medical use).
4. Stir the solution thoroughly to ensure the bacitracin is evenly distributed.
5. Label the vial or container with the concentration (1 uM) and the date.
6. If there is any excess chemical remaining, it should be properly disposed of according to your local regulations for chemical waste.
So, your final answer would be to measure out 4.586 mg of bacitracin and dissolve it in water to make 10 ml of the desired 1 uM concentration solution.