math
posted by Jay .
find the integral
secxtanxdx
and
if dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to
and differentiate
2pi + 3secx
secxtanxdx =
Sin(x)/Cos^2(x)dx
The integral is 1/Cos(x) + c
dy/dx= 2x/y^2 and y(o) = 3 then what is y(1) equal to
y^2 dy = 2x dx >
1/3 y^3 = x^2 + c
y(0) = 3 >
c = 9
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