# Mathematics

posted by
**London**
.

How would you solve for:

(the square root of 7-the square root of 3)^2

^=the power of

[sqrt(7) - sqrt(3)]^2 =

7 + 3 - 2sqrt(21) = 10 - 2sqrt(21)

posted by
**London**
.

How would you solve for:

(the square root of 7-the square root of 3)^2

^=the power of

[sqrt(7) - sqrt(3)]^2 =

7 + 3 - 2sqrt(21) = 10 - 2sqrt(21)