I need help with the heat effects and calorimetry worksheet. Please explain how to solve it! Thank you so much!
A metal sample weighing 45.2g and at a temperature of 100.0 C was placed in 38.6g of water in a calorimeter at 25.6 C. At equilibrium the temperature of the water and meter was 32.5 C.
What was the delta t for the water?
What was the delta t for the metal?
How much heat flowed into the water?
Taking the specific heat of water to be 4.18 J/g C, calculate the specific heats of meatl using Eq. 3.
What is the approximate molar mass of the metal? (Use Eq. 4.)
I assume that you mean "metal" where you wrote "meatl" and "meter".
"delta T" is the temperature change. Calculating them is simply a matter of subtracting the initial from the final temperature. Do that.
The heat that flows into the water is
(water mass) x (specific heat) x (delta T of water)
Calculate that.
Use your equation 4, whatever it is, for the last part.
Show your work if you required further help.
Sure, here's how you can solve the worksheet problems step by step:
1. Delta T for the water:
Delta T = Final temperature - Initial temperature
Delta T = 32.5 C - 25.6 C
Delta T = 6.9 C
2. Delta T for the metal:
Delta T = Final temperature - Initial temperature
Delta T = 32.5 C - 100.0 C
Delta T = -67.5 C
Note: The negative sign indicates that the metal sample lost heat and its temperature decreased.
3. Heat flowed into the water:
Heat = (water mass) x (specific heat of water) x (delta T of water)
Heat = 38.6g x 4.18 J/g C x 6.9 C
Heat = 1121.572 J or approximately 1122 J
4. Calculation of specific heat of the metal using Equation 3:
Equation 3 is not stated in your question, so I cannot provide a specific answer for this step. Please refer to your worksheet or textbook to find the equation mentioned and use it to calculate the specific heat of the metal.
5. Approximate molar mass of the metal using Equation 4:
Again, Equation 4 is not provided in your question, so I cannot give a specific answer for this step. Please refer to your worksheet or textbook to find the equation mentioned and use it to calculate the approximate molar mass of the metal.
If you need further assistance or have any other questions, feel free to ask!
To solve the heat effects and calorimetry worksheet, follow these steps:
1. Calculate the delta t for the water:
Delta t_water = Final temperature - Initial temperature
= 32.5°C - 25.6°C
= 6.9°C
2. Calculate the delta t for the metal:
Delta t_metal = Final temperature - Initial temperature
= 32.5°C - 100.0°C
= -67.5°C
3. Determine the heat that flowed into the water:
Heat_water = (water mass) x (specific heat of water) x (delta t_water)
= 38.6g x 4.18 J/g°C x 6.9°C
= 1121.02 J
4. Calculate the specific heat of the metal using Equation 3:
Heat_metal = (metal mass) x (specific heat of metal) x (delta t_metal)
The heat that flowed into the water (1121.02 J) is equal to the heat that flowed out of the metal.
Therefore, we can solve for the specific heat of the metal using the known values:
1121.02 J = 45.2g x (specific heat of metal) x (-67.5°C)
Specific heat of metal = 1121.02 J / (45.2g x -67.5°C)
5. Use Equation 4 to calculate the approximate molar mass of the metal:
Mass of metal = (mass of metal sample) / (moles of metal)
Moles of metal = (mass of metal sample) / (molar mass of metal)
Rearrange the equation to solve for the molar mass of the metal:
Molar mass of metal = (mass of metal sample) / (moles of metal)
= (45.2g) / (moles of metal)
Please note that you would need to provide the equation mentioned in step 4 for a specific calculation, as it is not specified in your question. Let me know if you need any further assistance!
To solve the heat effects and calorimetry worksheet, let's start by calculating the delta T (temperature change) for the water and the metal.
1. Delta T for water:
Delta T = Final temperature - Initial temperature
Delta T = 32.5°C - 25.6°C
Delta T = 6.9°C
2. Delta T for the metal:
Delta T = Final temperature - Initial temperature
Delta T = 32.5°C - 100.0°C
Delta T = -67.5°C
Now, let's calculate the heat flow into the water and the specific heats of the metal.
3. Heat flowed into the water:
The heat flow into the water can be calculated using the formula:
Heat = (mass of water) x (specific heat of water) x (delta T of water)
Given:
Mass of water = 38.6g
Specific heat of water = 4.18 J/g°C
Delta T of water = 6.9°C
Heat = 38.6g x 4.18 J/g°C x 6.9°C
Heat = 1088.6316 J
Therefore, approximately 1089 J of heat flowed into the water.
4. Specific heats of the metal:
The specific heat of the metal can be calculated using Equation 3. You will need additional information or equations to proceed with this calculation. Please refer to Equation 3 in your worksheet or provide more details so that I can guide you appropriately.
5. Approximate molar mass of the metal:
To calculate the approximate molar mass of the metal, you can utilize Equation 4 mentioned in your worksheet. Again, you need to provide the equation or additional information related to Equation 4 so that I can assist you with the calculation.
Please provide any additional equations or information required, and I'll gladly help you further.