Why do beryllium and fluorine combine in a 1:2 ratio?
use page 194 in your textbook.
Be is in group 2 (IIA) and has two electrons in its outer shell which it wants to give away. Flourine is in group 17 (VIIA) and has seven electrons. It needs one more to fill its outside shell. So two F atoms are needed per one Be
Because beryllium has two plus charge and fluorine has a one minus charge to make the two have property, you'll need 1Br and 2F which would then be BeF2.
Ionic compounds
According to page 194 in your textbook, beryllium (Be) is classified under group 2 (IIA) and has two electrons in its outer shell. Beryllium tends to give away these two electrons in order to achieve a stable electron configuration. On the other hand, fluorine (F) is in group 17 (VIIA) and has seven electrons in its outer shell. It needs one additional electron to fill its outer shell and attain a stable electron configuration.
To satisfy the electron requirements of both beryllium and fluorine, a 1:2 ratio is formed. This means that two fluorine atoms are needed to accept the two electrons given by one beryllium atom. By combining beryllium and fluorine in a 1:2 ratio, both elements fulfill their electron requirements and achieve a stable electron configuration.
Beryllium (Be) and fluorine (F) combine in a 1:2 ratio because of their electron configurations. Beryllium is in group 2 (IIA) of the periodic table, which means it has two electrons in its outermost shell. Beryllium prefers to lose these two electrons to achieve a stable configuration, as elements in group 2 tend to lose their outermost electrons in chemical reactions.
On the other hand, fluorine is in group 17 (VIIA) and has seven electrons in its outermost shell. Fluorine needs to gain one more electron to complete its outer shell and achieve a stable configuration. Elements in group 17 tend to gain one electron during chemical reactions.
To understand why beryllium and fluorine combine in a 1:2 ratio, you can refer to the periodic table or your textbook. On page 194 of your textbook, you can find the electron configurations of beryllium and fluorine. This information will confirm that beryllium wants to lose two electrons, while fluorine needs to gain one electron.
Therefore, in order to balance the transfer of electrons and achieve stability, two fluorine atoms are needed to bond with one beryllium atom. Each fluorine atom gains one electron from the beryllium atom, allowing both elements to achieve a stable electron configuration. This results in the formation of beryllium fluoride (BeF2), with the atoms arranged in a 1:2 ratio.