Inter. Algebra
posted by Andrea .
Another problem plz help Count Iblis. How do you solve 5/x+2 + 2x/x squared  4= 3/x2?
5/x+2 + 2x/x squared  4= 3/x2
You write the term:
2x/x squared as 2/x
the equation becomes:
5/x+2 + 2/x  4= 3/x2
4/x = 0
This equation has no solutions. It is only satisfied in the limit x > infinity.
If you take x to be any nonzero number and multiply both sides by x, you obtain the equation:
4 = 0,
which is always false! So, assuming that there is a solution you arrive at a contradiction, so the assumption that a solution exists must be false.
can I ask you another question? what is the answer to 4= square root sign with x2 underneath it?
4 = sqrt[x 2] >
16 = x  2 And x >=2 >
x  2 = 16 And x  2 >= 0 >
x = 18
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