Another Problem...PLz Help COunt Iblis
posted by Margie... .
Statements Reasons
1. 3x  7 = 4
2. 3x  7 + 7 = 4 + 7
3. 3x + 0 = 4 + 7
4. 3x + 0 = 3
5. 3x = 3
6. (1/3) 3x = 3 (1/3)
7. (1/3) 3x = 1
8. 1x = 1
9. x = 1
Is this problem about explaining each step?
yeah like you have to write the property of each
Are you going to help?PLease do!
Hmmm, I don't know if I can do it in the way you are supposed to do it.
I think you are asked to just write down what ahppens in each step. E.g.
7 + 7 = 0, because 7 is the inverse w.r.t. addition to 7.
In another step it is used that 3x + 0 = 3x. Here you use the definition of the zero element. that x + 0 = x for all x.
in another you see that 1/3*3*x = 1*x is used. Here you use that:
a*b*c = (a*b)*c
and that
1/3 is the inverse w.r.t. multiplication of 3.
and in another step you see that
1*x = x is used.
here the property of the unit element is used. 1*x = x because 1 is the unit element w.r.t. multiplication.
That is how you do it but can you help me then?
I think you can just use use what I wrote. There is nothing more to this problem than using the definitions of minus a number and 1/number as the inverses w.r.t. addition and multiplication and the unit elements 0 for addition and 1 for multiplication.
so can you write the answers next to the numbers
ex.1.dfgb
2.sdfhvn
PLZ and thanks
Ok, I'm not sure you are suppose to do it like this:
1. 3x  7 = 4
Add 7 to both sides (+7 is the inverse of 7 w.r.t. addition, this wil yield zero and zero added to 3x will leave the 3x invariant):
2. 3x  7 + 7 = 4 + 7
Now we use that 7 + 7 = 0:
3. 3x + 0 = 4 + 7
Next step is 4 + 7 = 3
4. 3x + 0 = 3
Here we use that 0 is the unit lelemnt w.r.t. addition.
5. 3x = 3
Next we multiply both sides by 1/3:
6. (1/3) 3x = 3 (1/3)
1/3 is the inverse w.r.t. multiplication of 3. we use this on the right hand side:
7. (1/3) 3x = 1
And again in the left hand side.
8. 1x = 1
1*x = x, becuase 1 is the unit w.r.t. multiplication:
9. x = 1
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