Math
posted by Sam .
Amy has a collection of X,Y, and Z's. Every X is a Y. Onehalf the Z's are Y's. There are 3 times as many Y's as X's. Amy has 50 Z's and 40X's.
No Z in an X.
How many Y's does Amy have that are neither X's nor Z's?
I found drawing a venn diagram helps solve this problem. There are 120 Ys, 40 XYs, and 25YZs. So, Ys only = 1204025 = 55
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