e^3x-5=17
Dee: You need to use closure marks. It is impossible to decipher your questions without them.
Is this: e^(3x-5)=17
e3x-5=17
or e^(3x)-5 =17
e3x-5 =17
Sorry for the confusion.
It is e^(3x-5)=17
e^(3x-5)=17
Take the ln (log base e) of each side.
3x-5= ln17
3x= ln 17 + 5
then divide by 3.
Ln 17 ...put that in the google search window
or put this in the google search window..
(ln 17 + 5)/3
To solve the equation e^(3x-5)=17, you can follow these steps:
Step 1: Take the natural logarithm (ln) of both sides of the equation. This helps to isolate the exponent (3x-5) and convert it into a simpler form.
ln(e^(3x-5)) = ln(17)
Step 2: Simplify the left side using the logarithmic property ln(e^a) = a.
3x-5 = ln(17)
Step 3: Add 5 to both sides of the equation.
3x = ln(17) + 5
Step 4: Divide both sides of the equation by 3 to solve for x.
x = (ln(17) + 5)/3
To find the value of (ln(17) + 5)/3, you can use the Google search window. Simply type "(ln 17 + 5)/3" (without the quotes) into the search bar, and it will provide you with the numerical result.