# algebra

posted by
**dee**
.

e^3x-5=17

Dee: You need to use closure marks. It is impossible to decipher your questions without them.

Is this: e^(3x-5)=17

e^{3x-5}=17

or e^(3x)-5 =17

e^{3x}-5 =17

Sorry for the confusion.

It is e^(3x-5)=17

e^(3x-5)=17

Take the ln (log base e) of each side.

3x-5= ln17

3x= ln 17 + 5

then divide by 3.

Ln 17 ...put that in the google search window

or put this in the google search window..

(ln 17 + 5)/3