# algebra

posted by
**dee**
.

solve

4^3x-4=32^x+2

Please help!

Do you mean

4^(3x) -4 = 32^x +2 ?

yes

If that is really what you mean, I cannot get a closed-form solution for you. You would have to solve it by trial-and-error or graphical means. If, on the other hand, you mean

4^(3x-4)=32^(x+2), then take logs of both sides and get

(3x-4)log 4 = (x+2) log 32

[(3x-4)/(x+2)] = log [4^(5/2)]/log 4

[(3x-4)/(x+2)] = 2.5

3x - 4 = 2.5 x + 5

0.5 x = 9

x = 18