algebra

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solve

4^3x-4=32^x+2


Please help!

Do you mean
4^(3x) -4 = 32^x +2 ?

yes

If that is really what you mean, I cannot get a closed-form solution for you. You would have to solve it by trial-and-error or graphical means. If, on the other hand, you mean
4^(3x-4)=32^(x+2), then take logs of both sides and get
(3x-4)log 4 = (x+2) log 32
[(3x-4)/(x+2)] = log [4^(5/2)]/log 4
[(3x-4)/(x+2)] = 2.5
3x - 4 = 2.5 x + 5
0.5 x = 9
x = 18

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