Could someone write out the total ionic equation and the net ionic equation for:
2Na3PO4 (aq) + 3CuSO4 • 5H2O (aq) → Cu3 (PO4)2 (s) + 3Na3SO4 (aq) + 15H2O (l)
Cu++ + PO4--- >>> Cu3 (PO4)2 (s)
Of course, it needs to be balanced.
To write the total ionic equation and the net ionic equation, we need to break down the equation into its ionic components. Here's how you can do it:
1. Write the equation with the state symbols (s for solid, l for liquid, g for gas, and aq for aqueous solution).
2Na3PO4(aq) + 3CuSO4 • 5H2O(aq) → Cu3(PO4)2(s) + 3Na3SO4(aq) + 15H2O(l)
2. Split the compounds that are in aqueous solution into their individual ions. Sodium phosphate (Na3PO4) dissociates into three sodium ions (Na+) and one phosphate ion (PO43-). Copper sulfate pentahydrate (CuSO4 • 5H2O) dissociates into one copper ion (Cu2+), one sulfate ion (SO42-), and five water molecules (5H2O).
Total ionic equation:
6Na+(aq) + 2PO43-(aq) + 3Cu2+(aq) + 3SO42-(aq) + 15H2O(l) → Cu3(PO4)2(s) + 6Na+(aq) + 3SO42-(aq) + 15H2O(l)
3. Cancel out the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction. In this case, the sodium ions (Na+) and sulfate ions (SO42-) are spectator ions.
Net ionic equation:
2PO43-(aq) + 3Cu2+(aq) → Cu3(PO4)2(s)
Now the net ionic equation is balanced with the correct stoichiometric coefficients.
Cu++ + PO4--- >>> Cu3(PO4)2 (s)