chemistry
posted by Harry
A hydrate of strontium choloride contains 40.54% water. What is the formula of the hydrate ?
SrCl2*xH2O.
H2O = 40.54%
SrCl2 = 100  40.54 = 59.46%
Take 100 g sample. This gives us
59.46g SrCl2 and 40.54g H2O.
Convert to mols.
mols SrCl2 = 59.46/158.5 = 0.375
mols H2O = 40.54/18.02 = 2.25
So the formula is (SrCl_{2})_{0.375}*2.5 H_{2}O
But we want whole numbers; therefore, divide the smaller number by itself to obtain 1 (0.375/0.375 = 1.00) and divide the other number by 0.375. That should give you the whole number ratio. Post your work if you get stuck.
Thank you for your help. Yes i got the answer 6H20
Thank you for your help
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