I'm not sure how to multiply (x^2+6x=9) by (x^2-1)
I would assume that you would have to distribute everything as normal, including the 9 ( the answer being x^4-x^2+6x^3-6x=9x^2-9)but I am really not sure because I havent done something like this before.
To multiply polynomials, such as (x^2 + 6x = 9) and (x^2 - 1), you will indeed need to distribute each term from one polynomial to every term in the other polynomial. Here's a step-by-step guide to help you solve this problem:
1. Start by distributing each term from the first polynomial (x^2 + 6x = 9) to every term in the second polynomial (x^2 - 1):
(x^2 + 6x - 9) * (x^2 - 1)
2. Multiply each term in the first polynomial by every term in the second polynomial:
x^2 * x^2 + x^2 * (-1) + 6x * x^2 + 6x * (-1) - 9 * x^2 - 9 * (-1)
Simplify the expression:
x^4 - x^2 + 6x^3 - 6x - 9x^2 + 9
3. Combine like terms:
x^4 + 6x^3 - x^2 - 9x^2 - 6x + 9
4. Simplify further:
x^4 + 6x^3 - 10x^2 - 6x + 9
Therefore, the final answer after multiplying (x^2 + 6x = 9) by (x^2 - 1) is x^4 + 6x^3 - 10x^2 - 6x + 9.
Remember, to multiply polynomials, you distribute each term from one polynomial to every term in the other polynomial and then combine like terms.