Calc
posted by Norris .
A car traveling at 43 ft/sec decelerates at a constant 5 feet per second squared. How many feet does the car travel before coming to a complete stop?
i tried a few different equations, none of the worked.
43t  5t^2 = 0
43  10t = 0
21.5t^2  (5/3)t^3 = 0
maybe im not supposed to set it to zero? i don't know what to do
This looks like the "antiderivative" question I answered earlier this evening.
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