# Calc

posted by
**Norris**
.

A car traveling at 43 ft/sec decelerates at a constant 5 feet per second squared. How many feet does the car travel before coming to a complete stop?

i tried a few different equations, none of the worked.

43t - 5t^2 = 0

43 - 10t = 0

21.5t^2 - (5/3)t^3 = 0

maybe im not supposed to set it to zero? i don't know what to do

This looks like the "anti-derivative" question I answered earlier this evening.