# Physics

posted by
**Min**
.

A bullet is fired horizontally from the roof of a building 100 meters tall with a speed of 850 m/s. Neglecting air resistance, how far will the bullet drop in 3 seconds?

1 29.4 m

2 44.1 m

3 100 m

4 2550 m

Answer should be choice 2) 44.1m

BUT I DON'T GET IT!

Please help me;(

if i remember the formula correctly as:

x = (-9.8/2)t^2 + vt + x0

x = (-9.8/2)(3^2)

x = 44.1 m

You split up this problem into horizontal and vertical components like below:

a = acceleration

v = velocity

x = distance

x0 = starting distance (usually 0)

t = time

Vertical:

a = -9.8m/s^2

v = none (they said that the bullet was shot horizontally so vertically, it would be like the velocity at the peak of a free-fall.

x = 100 m

x0 = 0 m (this is like the starting point of the fall so technbically 0)

Horizontal:

a = none (gravity doesn't move sideways and there's no given acceleration)

v = 850m/s

x = (not given)

x0 = (not given)

:)