math
posted by Rory .
Factor 2x²+13x+40
I thought with this sort of problem you are supposed to multipy 40 by 2 and get 80 and then come up with two factors that equal 13. If this doesn't work, you are supposed to factor out a number/variable.
Since neither of these methods work, is this problem unable to be factored, or am I mistaken?
Thanks in advance.
i thought it would be 15x3+40. I am not sure though
I don't think it can be factored. The factors of 40 are
40*1
20*2
10*4
8*5
and none of those number will work.
For
a x^2 + bx + c
calculate the discriminant:
b^2  4 a c.
If it is negative it cannot be factored.
In this case it is 151. The factorization involves the square root of the discriminant. If it isn't rational you won't be able to find the factorization by inspection easily either.
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