Two objects, each with a charge of +3·10-6 C, are located 7 m apart.

What is the electric force between them?

Use coulombs equation: I will be happy to critique your work.

To calculate the electric force between two charged objects, we can use Coulomb's equation:

F = k * (q1 * q2) / r^2

Where:
F is the electric force between the objects,
k is the electrostatic constant (k = 8.99 x 10^9 N m^2/C^2),
q1 and q2 are the charges of the objects in coulombs, and
r is the distance between the objects in meters.

Given:
q1 = +3 * 10^-6 C
q2 = +3 * 10^-6 C
r = 7 m

Now, let's substitute the values into the equation:

F = (8.99 x 10^9 N m^2/C^2) * ((3 x 10^-6 C) * (3 x 10^-6 C)) / (7 m)^2

F = (8.99 x 10^9 N m^2/C^2) * (9 x 10^-12 C^2) / 49 m^2

F ≈ 1.63 x 10^-8 N

Therefore, the electric force between the two objects is approximately 1.63 x 10^-8 Newtons.