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A 50 kg skier is pulled up a frictionless ski slope that makes an angle of 8 degrees with the horizontal by holding onto a tow rope that moves parallel to the slope. Determine the magnitude of the force of the rope on the skier at an instant when a) the rope is moving with a constant speed of 2 m/s and b) the rope is moving with a constant speed of 2 m/s but that speed is increasing at a rate of .10 m/s^2.

I would need to use F=ma but how would i do this if there is a v involved? I also don't get part b) becasue of the speed that is increasing at a rate of .10 m/s^2

Ren (Lars) Stop posting under multiple names.

Constant speed is zero acceleration. So you are dealing with just force here, the up the slope forces equal the down the slope forces.

Now when there is a changing speed, there is a net acceleration.

Net force= mass*acceleration
When acceleration is zero,
Net force = UPForce -DOWNforce=0
When acceleration is not zero.
UPforce - Downforce= mass*acceleratin

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