algebra
posted by Dee Williams .
logarithms
Solve the following equations
3^x2=6
Add 2 to both sides of the equation to start. Whatever operation you do to one side of an equation you must do to the other side as well.
3^x  2 + 2 = 6 + 2
3^x = 8
Changing to logs:
log 3^x = log 8
x log 3 = log 8
x = log 8 / log 3
x = 1.8928 >this is a rounded value.
This should check with the original equation.
I hope this helps.
Respond to this Question
Similar Questions

Variable
SOLVING EQUATIONS WITH THE VARIABLE ON BOTH SIDES Solve the equation. Then check your solution. 4x9 = 7x+12 Just remember that one can add, subtract, multiply, divide, etc but whatever is done to one side must be done to the other … 
algerbra 1
what is the answer to 5x16=145x Just giving you the answer is not what this forum is about. We'd be defeating the purpose of you assignment by doing that. Try to work the variables to one side, say the lefthand side, and the numbers … 
algebradistributive
how would you do this prob. negative4(5y+6) = negative 7y+3 thanks. happy halloween I'm going to assume your problem is this: 4  (5y + 6) = 7y + 3 If that's the case, distribute the negative over the terms in the parentheses first: … 
Algebra
 20> 8 +7a Solve inequalities like you would an equation, EXCEPT if you multiply or divide by a negative number, reverse the inequality sign. Let's look at your problem:  20 > 8 + 7a First subtract 8 from both sides (whatever … 
Pre Cal
6x=2x+9 If you are to solve the equation for x, first try to get the variable on one side of the equation. Let's subtract 2x from both sides to start (whatever operation you do to one side of an equation you must do to the other side … 
Math
A=1/2H(B+b) Solve for H Let's start by getting rid of the fraction. Multiply both sides by 2 (whatever operation you do to one side of an equation you must do to the other side as well): 2(A) = 2[1/2H(B+b)] 2A = H(B+b) Now divide both … 
MATH PLEASE CHECK IT!!2
m2/m5*m+5/m2=1 If your problem is this: (m  2)/(m  5) * (m + 5)/(m  2) = 1 (m  2) cancels out in both the numerator and denominator on the lefthand side since you are multiplying. That leaves us with this: (m + 5)/(m  5) … 
mathpre alg
not sure i did right 3(f+2)+9=13+5f 3f+6+9 = 13+5f +9 3F+15 = 12+5F GOT MIXED UP SOMWERE HELP 3f +6 +9 = 13 + 5f 3f + 15 = 13 + 5f 2f = 2 f = 1 drwls is correct You are doing OK up to this point: 3f + 6 + 9 = 13 + 5f Now combine any … 
Math
q + 13 = 120 __ 8 I'm going to assume your problem is this: (q/8) + 13 = 120 If so, start by subtracting 13 from both sides of the equation. Whatever operation you do to one side of an equation you must do to the other side as well. … 
math
2r+4=10 Well r=3 so that means 2xr=6 and 6+4=10. Hint: whenever a number and letter are close together you have to multply thme like 2r. The value for r is indeed 3! Another way to think about this problem is to start by subtracting …